Solve the equation. Check for extraneous solutions. $\frac { 48 } { y + 5 } + \frac { 1 } { 2 } = 2$
A) y=25
B) y=31
C) y=23
D) y=29
E) y=27

Name: Solve the equation. Check for extraneous solutions. $\frac { 48 } { y + 5 } + \frac { 1 } { 2 } = 2$ A) y=25 B) y=31 C) y=23 D) y=29 E) y=27
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The Answer of Solve the equation. Check for extraneous solutions. $\frac { 48 } { y + 5 } + \frac { 1 } { 2 } = 2$
A) y=25
B) y=31
C) y=23
D) y=29
E) y=27

Solve the Equation 48y+5+12=2\frac { 48 } { y + 5 } + \frac { 1 } { 2 } = 2y+548​+21​=2

Solve the Equation $\frac { 48 } { y + 5 } + \frac { 1 } { 2 } = 2$