Solve the equation. Check for extraneous solutions. $10 - \frac { 60 } { 4 - x } = \frac { 10 x + 20 } { x ^ { 2 } - 16 }$
A) $x = - 30 ; x = 20$
B) $x = - 3 ; x = - 2$
C) $x = 7 ; x = 5$
D) $x = 3 ; x = 2$
E) $x = - 7 ; x = - 5$

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The Answer of Solve the equation. Check for extraneous solutions. $10 - \frac { 60 } { 4 - x } = \frac { 10 x + 20 } { x ^ { 2 } - 16 }$
A) $x = - 30 ; x = 20$
B) $x = - 3 ; x = - 2$
C) $x = 7 ; x = 5$
D) $x = 3 ; x = 2$
E) $x = - 7 ; x = - 5$

Solve the Equation 10−604−x=10x+20x2−1610 - \frac { 60 } { 4 - x } = \frac { 10 x + 20 } { x ^ { 2 } - 16 }10−4−x60​=x2−1610x+20​

Solve the Equation $10 - \frac { 60 } { 4 - x } = \frac { 10 x + 20 } { x ^ { 2 } - 16 }$