Solve the equation. Do not use a calculator. $$\log _ { 6 } ( 2 x + 9 ) = \log _ { 6 } ( 4 x + 5 )$$
A) $x = 2$
B) $x = - 7$
C) $x = 7$
D) $x = - 2$
E)no solution

Name: Solve the equation. Do not use a calculator. \[\log _ { 6 } ( 2 x + 9 ) = \log _ { 6 } ( 4 x + 5 )\] A) $x = 2$ B) $x = - 7$ C) $x = 7$ D) $x = - 2$ E)no solution
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Question

Quizplus · Accepted Answer

Since the bases of the logarithms are the same, the arguments must be equal. Thus, $2x + 9 = 4x + 5$. Solving for $x$ gives $x = 2$.

Solve the Equation log⁡6(2x+9)=log⁡6(4x+5)\log _ { 6 } ( 2 x + 9 ) = \log _ { 6 } ( 4 x + 5 )log6​(2x+9)=log6​(4x+5)

Solve the Equation $\log _ { 6 } ( 2 x + 9 ) = \log _ { 6 } ( 4 x + 5 )$