Factor the trinomial completely.
A) ( y - 2)(16 y - 12)
B) 16 ( y + 1)( y - 3)
C) 4 ( y + 2)(4 y - 3)
D) (4 y + 8)(4 y - 3)
E) not factorable

Question

Factor the trinomial completely. 
A) ( y - 2)(16 y - 12) 
B) 16 ( y + 1)( y - 3) 
C) 4 ( y + 2)(4 y - 3) 
D) (4 y + 8)(4 y - 3) 
E) not factorable

Quizplus · Accepted Answer

We can use the AC method to factor this trinomial. The product of 11 and -24 is -264. We want to find two factors of -264 that add up to -2. After some trial and error, we see that -12 and 22 are the two factors we need. Therefore, we can write the trinomial as:

11y^2 - 2y - 24y + 4 = 11y(y - 2) - 4(6y - 1) = ( y - 2)(11y - 4)

From here, we can simplify further to get:

( y - 2)(4y + 8/11) = 4 ( y + 2)(4 y - 3)

Therefore, the answer is C.

Factor the Trinomial Completely