You are installing an OLTP application on a new server. The I/O profile of the application consists of 100% random read operations of 8 kilobyte transfers. You need to determine which HBA to use in your application to accommodate 50,000 IOPS. What is the minimum FC link speed that will satisfy the application's requirements?
A) 1 Gbps
B) 2 Gbps
C) 4 Gbps
D) 8 Gbps

Question

Quizplus · Accepted Answer

To calculate the required FC link speed, multiply the IOPS by the transfer size and convert to Gbps: 50,000 IOPS * 8 KB = 400,000 KB/s = 400 MB/s. Converting to Gbps: 400 MB/s * 8 = 3.2 Gbps. Therefore, a 4 Gbps link is the minimum required.

You Are Installing an OLTP Application on a New Server