In the following reaction: HA ⇌ H⁺ + A^- , what is the pH value if [HA] = 0.300 M and K = 1 × 10^-5?

Question

Quizplus · Accepted Answer

The pH is calculated using the formula pH = -log[H⁺]. For the reaction HA ⇌ H⁺ + A⁻, the concentration of H⁺ is determined by the equilibrium expression K = [H⁺][A⁻]/[HA]. Assuming x is the concentration of H⁺ at equilibrium, K = x²/(0.300 - x) ≈ x²/0.300. Solving for x gives x ≈ 1.73 × 10⁻³, so pH = -log(1.73 × 10⁻³) ≈ 2.76.

In the Following Reaction: HA ⇌ H+ + A-

In the Following Reaction: HA ⇌ H⁺ + A^-