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For the Equation for a Normal Distribution Shown, What Are f(x)=132πe(x16)232f(x)=\frac{1}{\sqrt{32 \pi}} e^{\frac{-(x-16)^{2}}{32}}

Question 2

Multiple Choice

For the equation for a normal distribution shown, what are the mean and variance?
?
f(x) =132πe(x16) 232f(x) =\frac{1}{\sqrt{32 \pi}} e^{\frac{-(x-16) ^{2}}{32}}


A) Mean = 4, variance = 4
B) Mean = 4, variance = 16
C) Mean = 16, variance = 4
D) Mean = 16, variance = 16

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