The number Cof chipmunks in a small rural township t days after May 1, 2015, follows the logistic model $\frac { d C } { d t } = 1.56 C \left( 1 - \frac { C } { 2,000 } \right)$ . The number of chipmunks recorded on May 1, 2015, was 775. What is the carrying capacity in this scenario?

A)1.56 thousand chipmunks
B) $1 - \frac { C } { 2,000 }$ chipmunks
g
C) $\frac { 1.56 } { 2,000 }$ chipmunks
D)2,000 chipmunks
E)775 chipmunks

Question

The number Cof chipmunks in a small rural township t days after May 1, 2015, follows the logistic model

\frac { d C } { d t } = 1.56 C \left( 1 - \frac { C } { 2,000 } \right)

. The number of chipmunks recorded on May 1, 2015, was 775. What is the carrying capacity in this scenario?

A)1.56 thousand chipmunks
B) $1 - \frac { C } { 2,000 }$ chipmunks
 g
C) $\frac { 1.56 } { 2,000 }$ chipmunks
D)2,000 chipmunks
E)775 chipmunks

Quizplus · Accepted Answer

The carrying capacity in a logistic model is the maximum population size that the environment can sustain indefinitely. It is represented by the denominator in the fraction of the growth term, which in this case is 2,000.

The Number Cof Chipmunks in a Small Rural Township T dCdt=1.56C(1−C2,000)\frac { d C } { d t } = 1.56 C \left( 1 - \frac { C } { 2,000 } \right)dtdC​=1.56C(1−2,000C​)

The Number Cof Chipmunks in a Small Rural Township T $\frac { d C } { d t } = 1.56 C \left( 1 - \frac { C } { 2,000 } \right)$