The surface area of the surface $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 9$ above z = 0 and inside $x ^ { 2 } + y ^ { 2 } = 3 x$ is

A) $\frac { \pi ( 7 \sqrt { 21 } - 9 ) } { 2 }$
B) $\frac { \pi ( 7 \sqrt { 21 } - 9 ) } { 3 }$
C) $\frac { \pi ( 7 \sqrt { 21 } - 9 ) } { 6 }$
D) $9 ( \pi - 2 )$
E) $\frac { 9 ( \pi - 2 ) } { 2 }$

Question

The surface area of the surface $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 9$ above z = 0 and inside $x ^ { 2 } + y ^ { 2 } = 3 x$ is

A) $\frac { \pi ( 7 \sqrt { 21 } - 9 ) } { 2 }$
B) $\frac { \pi ( 7 \sqrt { 21 } - 9 ) } { 3 }$
C) $\frac { \pi ( 7 \sqrt { 21 } - 9 ) } { 6 }$
D) $9 ( \pi - 2 )$
E) $\frac { 9 ( \pi - 2 ) } { 2 }$

Quizplus · Accepted Answer

The Answer of The surface area of the surface $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 9$ above z = 0 and inside $x ^ { 2 } + y ^ { 2 } = 3 x$ is

A) $\frac { \pi ( 7 \sqrt { 21 } - 9 ) } { 2 }$
B) $\frac { \pi ( 7 \sqrt { 21 } - 9 ) } { 3 }$
C) $\frac { \pi ( 7 \sqrt { 21 } - 9 ) } { 6 }$
D) $9 ( \pi - 2 )$
E) $\frac { 9 ( \pi - 2 ) } { 2 }$

The Surface Area of the Surface x2+y2+z2=9x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 9x2+y2+z2=9

The Surface Area of the Surface $x ^ { 2 } + y ^ { 2 } + z ^ { 2 } = 9$