Let $f ( x ) = \left\{ \begin{array} { c c }
\frac { 9 } { x } & - 5

Question

Let $f ( x ) = \left\{ \begin{array} { c c } 
\frac { 9 } { x } & - 5 < x < - 3 \
2 & x = - 3 \
x & - 3 < x < 1
\end{array} \right.$ Which of the following is true for $\lim _ { x \rightarrow - 3 } f ( x )$ ?

A)-3
B)2
C)3
D)5
E)Does not exist

Quizplus · Accepted Answer

The Answer of Let $f ( x ) = \left\{ \begin{array} { c c } 
\frac { 9 } { x } & - 5 < x < - 3 \
2 & x = - 3 \
x & - 3 < x < 1
\end{array} \right.$ Which of the following is true for $\lim _ { x \rightarrow - 3 } f ( x )$ ?

A)-3
B)2
C)3
D)5
E)Does not exist

Let f(x)={9x−5<x<−32x=−3x−3<x<1f ( x ) = \left\{ \begin{array} { c c } \frac { 9 } { x } & - 5 < x < - 3 \\2 & x = - 3 \\x & - 3 < x < 1\end{array} \right.f(x)=⎩⎨⎧​x9​2x​−5<x<−3x=−3−3<x<1​

Let $f ( x ) = \left\{ \begin{array} { c c } \frac { 9 } { x } & - 5 < x < - 3 \\2 & x = - 3 \\x & - 3 < x < 1\end{array} \right.$