Use this information to answer the following questions.
$\begin{array}{l|c}
\text { Number of Servers } & 1.0 \
\text { Arrival Rate } & 7.00 \
\text { Service Rate } & 10.00 \
\mathrm{P}(0) \text {, probability that there are no customers in the system } & 30 \% \
\mathrm{Lq} \text {, average length of the queue } & 1.63 \
\mathrm{~W} \text {, average time in the system } & 0.33 \
\mathrm{~L} \text {, average number of customers in the system } & 2.33 \
\mathrm{Wq}, \text { average time in the queue } & 0.23 \
\text { Utilization factor of the system } & 70 \% \
\hline
\end{array}$

-Refer to the table.What is the average time a customer spends waiting in line and being served?
A)0.23
B)2.33
C)0.33
D)1.63
E)0.70

Question

Use this information to answer the following questions.
 $\begin{array}{l|c}
\text { Number of Servers } & 1.0 \
\text { Arrival Rate } & 7.00 \
\text { Service Rate } & 10.00 \
\mathrm{P}(0) \text {, probability that there are no customers in the system } & 30 \% \
\mathrm{Lq} \text {, average length of the queue } & 1.63 \
\mathrm{~W} \text {, average time in the system } & 0.33 \
\mathrm{~L} \text {, average number of customers in the system } & 2.33 \
\mathrm{Wq}, \text { average time in the queue } & 0.23 \
\text { Utilization factor of the system } & 70 \% \
\hline
\end{array}$

-Refer to the table.What is the average time a customer spends waiting in line and being served?
A)0.23
B)2.33
C)0.33
D)1.63
E)0.70

Quizplus · Accepted Answer

The average time a customer spends waiting in line and being served is given by $\mathrm{W}= \mathrm{Wq}+\dfrac{1}{\mu},$ where $\mu$ is the service rate. From the table, $\mathrm{Wq}=0.23$ and $\dfrac{1}{\mu}=\dfrac{1}{10}=0.10$. Therefore, $\mathrm{W}=0.23+0.10=0.33$.

Answer: None
 The information provided in the table is not sufficient to determine the best choice(s).

Use This Information to Answer the Following Questions -Refer to the Table