The specific heat capacity of liquid water is 4.18 J K^-1 g^-1. Calculate the temperature rise (in K) when 1050 J of heat is transferred to 5 mol of water.

Name: The specific heat capacity of liquid water is 4.18 J K -1 g -1 . Calculate the temperature rise (in K) when 1050 J of heat is transferred to 5 mol of water.
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Question

Quizplus · Accepted Answer

The specific heat capacity formula is q = mcΔT. Here, q = 1050 J, m = 5 mol × 18 g/mol = 90 g, and c = 4.18 J/g/K. Solving for ΔT gives ΔT = q / (mc) = 1050 / (90 × 4.18) = 2.79 K.

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