The spectra were recorded for a compound with a molecular formula C₅H₁₀O₂. Deduce the structure of this compound and explain how you arrive at the correct structure of the compound. (Hint: There are diastereotopic protons in this compound.) NOTE: In the NMR, after a D₂O shake, the triplet at $\delta$ 3.27 disappears, and the doublet at $\delta$ 3.7 becomes a singlet.

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The Answer of The spectra were recorded for a compound with a molecular formula C₅H₁₀O₂. Deduce the structure of this compound and explain how you arrive at the correct structure of the compound. (Hint: There are diastereotopic protons in this compound.) NOTE: In the NMR, after a D₂O shake, the triplet at $\delta$ 3.27 disappears, and the doublet at $\delta$ 3.7 becomes a singlet.

The Spectra Were Recorded for a Compound with a Molecular δ\deltaδ

The Spectra Were Recorded for a Compound with a Molecular $\delta$