Patients with infections are randomly selected and the number of distinct species belonging to the Spirochaete phylum (responsible for illnesses such as Lyme disease and syphilis) are recorded. Let X count the number of distinct species found. It is speculated that X follows a Poisson distribution with a mean of 0.25.
What is the standard deviation of the distribution of X?

Question

Quizplus · Accepted Answer

For a Poisson distribution, the standard deviation (sigma) is equal to the square root of the mean (lambda). Therefore, in this case, sigma = sqrt(0.25) = 0.5. Thus, the answer is C, 0.5000.

Patients with Infections Are Randomly Selected and the Number of Distinct