A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is A)14 cm² B)15 cm² C)16 cm² D)17 cm²

Question

Quizplus · Accepted Answer

The area of steel required can be calculated using the formula for bending moment and stress. The maximum bending moment for a simply supported beam with a uniformly distributed load is WL^2/8. Using the given values and permissible tensile stress, the area of steel required is approximately 16 cm².

A Simply Supported Beam 6 M Long and of Effective