If a secondary coil has 40 turns, and, a primary coil with 20 turns is charged with 50 V of potential difference, then the potential difference in the secondary coil would be
A)50 V in secondary coil
B)25 V in secondary coil
C)60 V in secondary coil
D)100 V in secondary coil

Question

Quizplus · Accepted Answer

The potential difference in the secondary coil can be calculated using the transformer equation: $V_s = V_p \times \frac{N_s}{N_p}$, where $V_s$ is the secondary voltage, $V_p$ is the primary voltage, $N_s$ is the number of turns in the secondary coil, and $N_p$ is the number of turns in the primary coil. Plugging in the given values: $V_s = 50V \times \frac{40}{20} = 100V$.

If a Secondary Coil Has 40 Turns, And, a Primary