A 10 m long cantilever beam is fixed at point B. What is the bending moment at point B, if 5 m span of AC carries uniform distributed load of 10 kN/m

Question

Quizplus · Accepted Answer

The bending moment at point B due to a uniformly distributed load (UDL) on a cantilever beam can be calculated using the formula $M = \frac{wL^2}{2}$, where $w$ is the load per unit length and $L$ is the length of the beam on which the load is acting. Here, $w = 10$ kN/m and $L = 5$ m, so $M = \frac{10 \times 5^2}{2} = \frac{10 \times 25}{2} = 125 \times 3 = 375$ kN/m, because the load acts on half the length of the beam but the moment is calculated at the fixed end B.

A 10 M Long Cantilever Beam Is Fixed at Point