What is the error in this code?
Byte b = 50;
B = b * 50;
A)b can not store the result 2500, limited by its range.
B)* operator has converted b * 50 into int, which can not be converted to byte without casting.
C)b can not contain value 50.
D)No error in this code

Question

Quizplus · Accepted Answer

The * operator in Java automatically promotes the operands to int when performing arithmetic operations, even if the operands are of a smaller type like byte. Therefore, the result of b * 50 is of type int, and assigning it back to a byte variable without explicit casting causes a compile-time error.

What Is the Error in This Code