Differentiate: $f ( x ) = \sqrt { x } + \frac { 1 } { \sqrt { x } }$
A) 0
B) x
C) $\frac { 1 } { 2 \sqrt { x } } + \frac { 1 } { 2 \sqrt { x ^ { 3 } } }$
D) $\frac { 1 } { 2 \sqrt { x } } - \frac { 1 } { 2 \sqrt { x ^ { 3 } } }$

Question

Quizplus · Accepted Answer

The derivative of $ \sqrt{x} $ is $ \frac{1}{2\sqrt{x}} $ and the derivative of $ \frac{1}{\sqrt{x}} $ is $ -\frac{1}{2\sqrt{x^3}} $.

Differentiate f(x)=x+1xf ( x ) = \sqrt { x } + \frac { 1 } { \sqrt { x } }f(x)=x​+x​1​

Differentiate $f ( x ) = \sqrt { x } + \frac { 1 } { \sqrt { x } }$