Consider an ideal capacitor C connected directly to an AC voltage source V. Summing voltage drops around the loop yields
A) $C + V Q = 0$
B) $V - C Q = 0$
C) $V + C Q = 0$
D) $V C - Q = 0$

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The Answer of Consider an ideal capacitor C connected directly to an AC voltage source V. Summing voltage drops around the loop yields
A) $C + V Q = 0$
B) $V - C Q = 0$
C) $V + C Q = 0$
D) $V C - Q = 0$

Consider an Ideal Capacitor C Connected Directly to an AC C+VQ=0C + V Q = 0C+VQ=0

Consider an Ideal Capacitor C Connected Directly to an AC $C + V Q = 0$