$f ( x ) = \left\{ \begin{array} { r r }
x ^ { 2 } + 3 & x

Name: $f ( x ) = \left\{ \begin{array} { r r } x ^ { 2 } + 3 & x < 0 \\ 3 - x & x \geq 0 \end{array} \right.$ Calculate $f ( - 1 ) , f ( 0 )$ and $f ( 2 )$
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Question

$f ( x ) = \left\{ \begin{array} { r r } 
x ^ { 2 } + 3 & x < 0 \
3 - x & x \geq 0
\end{array} \right.$ Calculate $f ( - 1 ) , f ( 0 )$ and $f ( 2 )$

Quizplus · Accepted Answer

The Answer of $f ( x ) = \left\{ \begin{array} { r r } 
x ^ { 2 } + 3 & x < 0 \
3 - x & x \geq 0
\end{array} \right.$ Calculate $f ( - 1 ) , f ( 0 )$ and $f ( 2 )$

f(x)={x2+3x<03−xx≥0f ( x ) = \left\{ \begin{array} { r r } x ^ { 2 } + 3 & x < 0 \\3 - x & x \geq 0\end{array} \right.f(x)={x2+33−x​x<0x≥0​

$f ( x ) = \left\{ \begin{array} { r r } x ^ { 2 } + 3 & x < 0 \\3 - x & x \geq 0\end{array} \right.$