Data Set 9-3: N = 8 $\Sigma$X = 48 $\Sigma$X 2 = 351 -The t value you calculated when the scores in Data Set 9-3 were tested against H₀: $\mu$ = 2.00 leads to the conclusion that the null hypothesis should be A) rejected at the .05 level for a two-tailed test B) rejected at the .05 and .01 level for a two-tailed test C) rejected at the .05, .01, and .001 level for a two-tailed test D) retained.

Question

Quizplus · Accepted Answer

The Answer of Data Set 9-3: N = 8 $\Sigma$X = 48 $\Sigma$X 2 = 351 -The t value you calculated when the scores in Data Set 9-3 were tested against H₀: $\mu$ = 2.00 leads to the conclusion that the null hypothesis should be A) rejected at the .05 level for a two-tailed test B) rejected at the .05 and .01 level for a two-tailed test C) rejected at the .05, .01, and .001 level for a two-tailed test D) retained.

Data Set 9-3: N = 8 Σ\SigmaΣ X = 48 Σ\SigmaΣ X2 = 351 -The T Value You Calculated When the \Sigma

Data Set 9-3: N = 8 $\Sigma$ X = 48 $\Sigma$ X² = 351
-The T Value You Calculated When the \Sigma