A 4 x 5 factorial ANOVA with six scores per cell produced a MS_AB = 40 and a MS_error = 20. For the factor with 5 levels and$\alpha$= .05, a Tukey HSD would A) not be appropriate in this instance B) find a mean difference of 3.60 significant C) find a mean difference of 3.80 significant D) find mean differences of both 3.60 and 3.80 significant E) find differences of neither 3.60 nor 3.80 significant.

Question

Quizplus · Accepted Answer

The Tukey HSD is not appropriate in this instance because the sample size is too small. The Tukey HSD is a multiple comparison procedure that is used to compare the means of multiple groups. However, it is only appropriate to use the Tukey HSD when the sample size is at least 20 per group. In this case, the sample size is only 6 per group, so the Tukey HSD is not appropriate.

A 4 X 5 Factorial ANOVA with Six Scores Per α\alphaα

A 4 X 5 Factorial ANOVA with Six Scores Per $\alpha$