Suppose a 5 x 6 factorial ANOVA with seven scores per cell produced MS_AB = 15, and MS_error = 10 (where A is the 5 in the 5 x 6). With $\alpha$= .01, a Tukey HSD for Factor A would A) not be appropriate in this instance B) be significant for a difference of 2.00 between two A means C) be significant for a difference of 2.40 between two A means D) find differences of 2.00 and 2.40 significant.

Question

Quizplus · Accepted Answer

The Tukey HSD test is used to find significant differences between group means. The critical value for Tukey's test depends on the number of groups and the error term. Given the MS values and $\alpha$= .01, a difference of 2.40 between two A means would be significant.

Suppose a 5 X 6 Factorial ANOVA with Seven Scores α\alphaα

Suppose a 5 X 6 Factorial ANOVA with Seven Scores $\alpha$