Assuming That, Since the Physical States Do Not Change, the Values

Assuming that, since the physical states do not change, the values of $\Delta$ H and $\Delta$ S do not change as we raise the temperature in the reaction below. Using the following values at 25 °C,
CaO(s) , $\Delta$ H°_f = -635.5 kJ mol^-1, S° = +40.0 J mol^-1 K^-1
CaCO₃(s) , $\Delta$ H°_f = -1207 kJ mol^-1, S° = +92.9 J mol^-1 K^-1
CO₂(g) , $\Delta$ H°_f = -394 kJ mol^-1, S° = +213.6 J mol^-1 K^-1
Calculate a value for the free energy change, $\Delta$ G°_T for the reaction,CaCO_3(s) $\rarr$ CaO(s) + CO₂(g) at 815 °C

A) +2.6 kJ mol^-1
B) +46.5 kJ mol^-1
C) -174.7 kJ mol^-1
D) +308.5 kJ mol^-1
E) -352.4 kJ mol^-1