Ores can be composed of many different components, including lead sulfide (PbS) . The amount of lead sulfide in an ore can be determined through the reaction: 2 PbS(s) + 6 HNO3(aq) + K2Cr2O7(aq) 2 PbCrO4(s) + 2 S(s) + 4 NO2(g) + 2 KNO3(aq) + 3 H2O If a 6.053 g sample of ore that was treated with excess nitric acid and potassium dichromate yielded 6.094 g of PbCrO4, calculate the percent, by weight, of lead sulfide in the ore. Hint: Convert the masses to moles and calculate as you would for other stoichiometric calculations.
A) 68.22%
B) 74.53%
C) 77.22%
D) 79.16%
E) 83.11%
Correct Answer:
Verified
Q192: The compound, X2O3, contains element X and
Q193: A compound which has the formula, Z2O3,
Q194: In a quantitative study, 4.624 grams of
Q195: A 5.000 g sample of a mixture
Q196: A mixture containing silver nitrate (AgNO3)and potassium
Q198: The mineral dolomite has the formula, CaCO3∙MgCO3.
Q199: A laboratory unknown is a mixture of
Q200: A chemistry graduate student needs to make
Q201: A chemistry graduate student needs to make
Q202: One way of making sodium chloride is
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents