Which of the following compounds (CH₄, CH₃Cl, CH₂Cl₂, CHCl₃ and CCl₄) are polar?

Question

Quizplus · Accepted Answer

Polarity arises due to the difference in electronegativity between the bonded atoms. In CCl₄, all the bonds are C-Cl bonds, and the electronegativity difference between C and Cl is 0.5. This difference is not enough to create a significant dipole moment, making CCl₄ nonpolar. In CH₄, all the bonds are C-H bonds, and the electronegativity difference between C and H is 0.4. This difference is also not enough to create a significant dipole moment, making CH₄ nonpolar. In CH₃Cl, the electronegativity difference between C and Cl is 0.5, and the electronegativity difference between C and H is 0.4. The vector sum of these two bond dipoles results in a net dipole moment, making CH₃Cl polar. In CH₂Cl₂, the electronegativity difference between C and Cl is 0.5, and the electronegativity difference between C and H is 0.4. The vector sum of these three bond dipoles results in a net dipole moment, making CH₂Cl₂ polar. In CHCl₃, the electronegativity difference between C and Cl is 0.5, and the electronegativity difference between C and H is 0.4. The vector sum of these four bond dipoles results in a net dipole moment, making CHCl₃ polar. Therefore, the correct answer is D.

Which of the Following Compounds (CH4, CH3Cl, CH2Cl2, CHCl3 and CCl4)

Which of the Following Compounds (CH₄, CH₃Cl, CH₂Cl₂, CHCl₃ and CCl₄)