Use the following information for Questions 3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πr 3 ; 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32) ‪ -Gold has a density of 19.282 g/cm³. What is the mass (in kg) of a sphere of solid gold with a radius of 6.0 cm? (The volume of a sphere is V = EQ \F(4,3) πr³ where r is the radius.)

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The Answer of Use the following information for Questions 3.785 L = 1 gallon; 2.2 lbs = 1 kg; V = EQ \F(4,3) πr 3 ; 1 in = 2.54 cm; 1 mile = 1.609 km; 12 in = 1 ft; 1 yard = 3 ft; 1 gal = 3.785 L; ˚C = 5/9 (˚F - 32) ‪ -Gold has a density of 19.282 g/cm³. What is the mass (in kg) of a sphere of solid gold with a radius of 6.0 cm? (The volume of a sphere is V = EQ \F(4,3) πr³ where r is the radius.)

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