Solved

Using Spherical Polar Coordinates, Find $\theta$ ) + Sin( )

Question 89

Multiple Choice

Using spherical polar coordinates, find $Using spherical polar coordinates, find . F for F = sin( \theta ) + sin( ) + cos( ) . A) 2 sin( ) + cos( ) - cot(1 1ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) B) 2 sin( ) + cos( ) - cot( ) C) 4 sin( ) + cos( ) - cot( ) D) 4 sin( ) + cos( ) - cot( ) E) 4 sin( ) - cos( ) - \theta cot( )$ . F for F = $Using spherical polar coordinates, find . F for F = sin( \theta ) + sin( ) + cos( ) . A) 2 sin( ) + cos( ) - cot(1 1ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) B) 2 sin( ) + cos( ) - cot( ) C) 4 sin( ) + cos( ) - cot( ) D) 4 sin( ) + cos( ) - cot( ) E) 4 sin( ) - cos( ) - \theta cot( )$ sin( $\theta$ ) $Using spherical polar coordinates, find . F for F = sin( \theta ) + sin( ) + cos( ) . A) 2 sin( ) + cos( ) - cot(1 1ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) B) 2 sin( ) + cos( ) - cot( ) C) 4 sin( ) + cos( ) - cot( ) D) 4 sin( ) + cos( ) - cot( ) E) 4 sin( ) - cos( ) - \theta cot( )$ + sin( $Using spherical polar coordinates, find . F for F = sin( \theta ) + sin( ) + cos( ) . A) 2 sin( ) + cos( ) - cot(1 1ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) B) 2 sin( ) + cos( ) - cot( ) C) 4 sin( ) + cos( ) - cot( ) D) 4 sin( ) + cos( ) - cot( ) E) 4 sin( ) - cos( ) - \theta cot( )$ ) $Using spherical polar coordinates, find . F for F = sin( \theta ) + sin( ) + cos( ) . A) 2 sin( ) + cos( ) - cot(1 1ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) B) 2 sin( ) + cos( ) - cot( ) C) 4 sin( ) + cos( ) - cot( ) D) 4 sin( ) + cos( ) - cot( ) E) 4 sin( ) - cos( ) - \theta cot( )$ + $Using spherical polar coordinates, find . F for F = sin( \theta ) + sin( ) + cos( ) . A) 2 sin( ) + cos( ) - cot(1 1ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) B) 2 sin( ) + cos( ) - cot( ) C) 4 sin( ) + cos( ) - cot( ) D) 4 sin( ) + cos( ) - cot( ) E) 4 sin( ) - cos( ) - \theta cot( )$ cos( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) 11ee77e1_779a_e1ef_a0f8_654af999776d_TB9661_11 .

A) 211ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 sin( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) + 11ee77e1_779a_e1f0_a0f8_63b455be4fbf_TB9661_11 cos( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) - 11ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 cot(1 1ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 )
B) 211ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 sin( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) + 11ee77e1_779a_e1f1_a0f8_7f4c97ed886c_TB9661_11 cos( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) - 11ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 cot( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 )
C) 411ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 sin( 11ee7bb1_d94a_cdb9_ae82_17500e2e2cd0_TB9661_11 ) + 11ee77e1_779a_e1f2_a0f8_f7c65261e663_TB9661_11 cos( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) - 11ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 cot(11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 )
D) 411ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 sin( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) + 11ee77e1_779a_e1f3_a0f8_95f1793f8e88_TB9661_11 cos( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) - 11ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 cot( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 )
E) 4 11ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 sin( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) - 11ee77e1_779a_e1f4_a0f8_a3f1f2174130_TB9661_11 cos( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 ) - 11ee7bb1_984f_5dd8_ae82_e9dd7cd34b51_TB9661_11 $\theta$ cot( 11ee7bb1_1f6d_7966_ae82_e9760b18acae_TB9661_11 )

Correct Answer: