Find the Cartesian equation of the straight line tangent to the plane curve given parametrically by the equations x(t) = + 2t + 2, y(t) = 1 - 3 - 2 at the point on the curve where t = -1.
A) x -3y -1 = 0
B) y =1
C) y = x + 1
D) 3x -y -3 = 0
E) y = 3x -7

Question

Find the Cartesian equation of the straight line tangent to the plane curve given parametrically by the equations x(t) =  + 2t + 2, y(t) = 1 - 3  - 2  at the point on the curve where t = -1.
A) x -3y -1 = 0 
B) y =1 
C) y = x + 1 
D) 3x -y -3 = 0 
E) y = 3x -7

Quizplus · Accepted Answer

The Answer of Find the Cartesian equation of the straight line tangent to the plane curve given parametrically by the equations x(t) =  + 2t + 2, y(t) = 1 - 3  - 2  at the point on the curve where t = -1.
A) x -3y -1 = 0 
B) y =1 
C) y = x + 1 
D) 3x -y -3 = 0 
E) y = 3x -7

Find the Cartesian Equation of the Straight Line Tangent to the Plane