Solving the equations P = 2 + 3Q and P = 6 + 3Q yields a solution for Q of:
A) 100.
B) -100.
C) 0.
D) no solution.

Name: Solving the equations P = 2 + 3Q and P = 6 + 3Q yields a solution for Q of: A) 100. B) -100. C) 0. D) no solution.
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Question

Quizplus · Accepted Answer

Since both equations are equal to P but have different constants (2 vs. 6) with the same coefficient for Q (3), they represent parallel lines, which means they will never intersect. Therefore, there is no solution for Q that satisfies both equations simultaneously.

Solving the Equations P = 2 + 3Q and P