Solve the problem.
-A BASE jumper's velocity (in meters per second) after t seconds is given by where m is the mass of the object in kilograms, g = 9.8 m/ s2 is the acceleration due to gravity, and k is a physical constant. How fast is the BASE jumper falling at the end of a 12 second delay? Use m = 75kg and k = 0.2 Round the answer to one decimal place if necessary.
A) 19.2 m/s
B) 58.2 m/s
C) 63.2 m/s
D) 698 m/s
Correct Answer:
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