Solve the problem.
-A frustum of a right circular cone has a height of 10 m, a base of radius 6m, and a top of radius 5m. Find its volume.
A) 91$\pi$
B) 910 /3 $\pi$
C) 91/3 $\pi$
D) 910$\pi$

Question

Quizplus · Accepted Answer

The volume of a frustum of a cone is given by the formula $V = \frac{1}{3}\pi h (r_1^2 + r_2^2 + r_1r_2)$, where $h$ is the height, $r_1$ and $r_2$ are the radii of the two bases. Substituting $h = 10$, $r_1 = 6$, and $r_2 = 5$, we get $V = \frac{1}{3}\pi \times 10 \times (6^2 + 5^2 + 6 \times 5) = \frac{1}{3}\pi \times 10 \times (36 + 25 + 30) = \frac{1}{3}\pi \times 10 \times 91 = 910/3 \pi$.

Solve the Problem π\piπ B) 910 /3 π\piπ C) 91/3 π\piπ D) 910 π\piπ

Solve the Problem $\pi$ B) 910 /3 $\pi$ C) 91/3 $\pi$ D) 910 $\pi$