Solve the problem.
-It takes 100 J of work to stretch a spring 1 m from its equilibrium position. How much work is needed to stretch it an additional 1 m?
A) 2500 J
B) 1500 J
C) 300 J
D) 500 J

Question

Solve the problem.   
-It takes 100 J of work to stretch a spring 1 m from its equilibrium position. How much work is needed to stretch it an additional 1 m?
A) 2500 J
B) 1500 J
C) 300 J
D) 500 J

Quizplus · Accepted Answer

The work needed to stretch a spring is proportional to the square of the displacement from its equilibrium position, according to Hooke's law. If 100 J is needed for the first meter, stretching it to 2 meters (twice the original distance) requires four times the work (since 2^2 = 4), making it 400 J in total. The additional work needed for the second meter is the difference: 400 J - 100 J = 300 J.

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