How many grams of MgO can be produced by burning 10.0 grams of Mg in the presence of 10.0 grams of O₂?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is 2Mg + O2 → 2MgO. The molar mass of Mg is 24.31 g/mol, and O2 is 32.00 g/mol. First, calculate moles of Mg: 10.0 g / 24.31 g/mol = 0.411 mol. Calculate moles of O2: 10.0 g / 32.00 g/mol = 0.3125 mol. According to the stoichiometry, 0.3125 mol of O2 can react with 0.625 mol of Mg, but only 0.411 mol of Mg is available, making Mg the limiting reactant. Thus, 0.411 mol of Mg will produce 0.411 mol of MgO. The molar mass of MgO is 40.31 g/mol, so 0.411 mol × 40.31 g/mol = 16.6 g of MgO.

How Many Grams of MgO Can Be Produced by Burning