A 2-kg mass is hung from a spring (k = 18 N/m), displaced slightly from its equilibrium position, and released. What is the frequency of its vibration?
A) 1.5 $\pi$Hz
B) 1.5 Hz
C) 3.0/ $\pi$ Hz
D) 1.5/ $\pi$Hz
E) 3.0 Hz

Question

A 2-kg mass is hung from a spring (k = 18 N/m), displaced slightly from its equilibrium position, and released. What is the frequency of its vibration?
A) 1.5  $\pi$Hz
B) 1.5 Hz
C) 3.0/ $\pi$ Hz
D) 1.5/ $\pi$Hz
E) 3.0 Hz

Quizplus · Accepted Answer

The frequency of vibration for a mass-spring system is given by $f = \frac{1}{2\pi}\sqrt{\frac{k}{m}}$, where $k$ is the spring constant and $m$ is the mass. Substituting $k = 18 \, \text{N/m}$ and $m = 2 \, \text{kg}$, we get $f = \frac{1}{2\pi}\sqrt{\frac{18}{2}} = \frac{1.5}{\pi} \, \text{Hz}$.

A 2-Kg Mass Is Hung from a Spring (K = π\piπ

A 2-Kg Mass Is Hung from a Spring (K = $\pi$