transverse wave travels at $230.0 \mathrm{~m} / \mathrm{s}$ along the $y$-axis. If the frequency of the periodic vibrations of the wave is $390.0 \mathrm{~Hz}$, then what is the wavelength of the wave?
A) $58.97 \mathrm{~cm}$
B) $36.76 \mathrm{~cm}$
C) $40.89 \mathrm{~cm}$
D) $68.97 \mathrm{~cm}$
E) $47.23 \mathrm{~cm}$

Question

Quizplus · Accepted Answer

The wavelength of a wave is given by the formula:$$\lambda = \frac{v}{f}$$where:* $\lambda$ is the wavelength* $v$ is the wave speed* $f$ is the frequencyIn this problem, we are given that the wave speed is $230.0 \mathrm{~m} / \mathrm{s}$ and the frequency is $390.0 \mathrm{~Hz}$. Substituting these values into the formula, we get:$$\lambda = \frac{230.0 \mathrm{~m} / \mathrm{s}}{390.0 \mathrm{~Hz}} = 0.5897 \mathrm{~m} = 58.97 \mathrm{~cm}$$Therefore, the wavelength of the wave is $58.97 \mathrm{~cm}$, which corresponds to choice A.

Transverse Wave Travels At 230.0 m/s230.0 \mathrm{~m} / \mathrm{s}230.0 m/s Along The yyy -Axis If the Frequency of the Periodic Vibrations of the y

Transverse Wave Travels At $230.0 \mathrm{~m} / \mathrm{s}$ Along The $y$ -Axis If the Frequency of the Periodic Vibrations of the y