A $3.7 \mathrm{pC}$ charge experiences a force of $8.1 \times 10^{-7} \mathrm{~N}$ in an electric field. What is the magnitude of the electric field?

Question

Quizplus · Accepted Answer

The magnitude of the electric field $E$ can be found using the formula $E = \frac{F}{q}$, where $F$ is the force experienced by the charge and $q$ is the magnitude of the charge. Substituting the given values, $E = \frac{8.1 \times 10^{-7} \mathrm{~N}}{3.7 \times 10^{-12} \mathrm{~C}} = 2.2 \times 10^{5} \mathrm{~N} / \mathrm{C}$.

A 3.7pC3.7 \mathrm{pC}3.7pC Charge Experiences a Force Of 8.1×10−7 N8.1 \times 10^{-7} \mathrm{~N}8.1×10−7 N

A $3.7 \mathrm{pC}$ Charge Experiences a Force Of $8.1 \times 10^{-7} \mathrm{~N}$