Solve the following system using one of the row echelon methods.
$\begin{aligned}
x+y+2 z & =4 \
3 x-2 y+4 z & =12 \
2 x-2 y+z & =1
\end{aligned}$

Name: Solve the following system using one of the row echelon methods. $\begin{aligned} x+y+2 z & =4 \\ 3 x-2 y+4 z & =12 \\ 2 x-2 y+z & =1 \end{aligned}$
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The Answer of Solve the following system using one of the row echelon methods.
$\begin{aligned}
x+y+2 z & =4 \
3 x-2 y+4 z & =12 \
2 x-2 y+z & =1
\end{aligned}$

Solve the Following System Using One of the Row Echelon x+y+2z=43x−2y+4z=122x−2y+z=1\begin{aligned}x+y+2 z & =4 \\3 x-2 y+4 z & =12 \\2 x-2 y+z & =1\end{aligned}x+y+2z3x−2y+4z2x−2y+z​=4=12=1​

Solve the Following System Using One of the Row Echelon $\begin{aligned}x+y+2 z & =4 \\3 x-2 y+4 z & =12 \\2 x-2 y+z & =1\end{aligned}$