Solved

Consider the Initial Value Problem This Question Relates to Using

Question 19

Multiple Choice

Consider the initial value problem  Consider the initial value problem   This question relates to using the Euler method to approximate the solution of this problem at t = 0.1 using a step size of h =   Which of the following equals    A)    y_{2}=\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    B)    y_{2}=\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    C)    y_{2}=1-\frac{1}{200}+\left({\frac{9}{200^{2}}}^{2}-1-\frac{1}{200}^{2}\right)    D)    y_{2}=1-\frac{1}{200}+\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)  This question relates to using the Euler method to approximate the solution of this problem at t = 0.1 using a step size of h =  Consider the initial value problem   This question relates to using the Euler method to approximate the solution of this problem at t = 0.1 using a step size of h =   Which of the following equals    A)    y_{2}=\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    B)    y_{2}=\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    C)    y_{2}=1-\frac{1}{200}+\left({\frac{9}{200^{2}}}^{2}-1-\frac{1}{200}^{2}\right)    D)    y_{2}=1-\frac{1}{200}+\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)  Which of the following equals  Consider the initial value problem   This question relates to using the Euler method to approximate the solution of this problem at t = 0.1 using a step size of h =   Which of the following equals    A)    y_{2}=\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    B)    y_{2}=\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)    C)    y_{2}=1-\frac{1}{200}+\left({\frac{9}{200^{2}}}^{2}-1-\frac{1}{200}^{2}\right)    D)    y_{2}=1-\frac{1}{200}+\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)


A) y2=1200(92002112002) y_{2}=\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)
B) y2=(92002112002) y_{2}=\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)
C) y2=11200+(920022112002) y_{2}=1-\frac{1}{200}+\left({\frac{9}{200^{2}}}^{2}-1-\frac{1}{200}^{2}\right)
D) y2=11200+1200(92002112002) y_{2}=1-\frac{1}{200}+\frac{1}{200}\left(\frac{9}{200^{2}}-1-\frac{1}{200}^{2}\right)

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents