Factor completely.
-$49 x^{2}+84 x+36$
A) $(7 x-6)^{2}$
B) Prime
C) $(7 x+6)(7 x-6)$
D) $(7 \mathrm{x}+6)^{2}$

Question

Quizplus · Accepted Answer

This quadratic expression can be factored as a perfect square trinomial. The square root of the first term $49x^2$ is $7x$, and the square root of the last term $36$ is $6$. The middle term $84x$ is twice the product of $7x$ and $6$, indicating that the expression can be factored as $(7x+6)^2$.

Factor Completely 49x2+84x+3649 x^{2}+84 x+3649x2+84x+36 A) (7x−6)2(7 x-6)^{2}(7x−6)2 B) Prime C) (7x+6)(7x−6)(7 x+6)(7 x-6)(7x+6)(7x−6)

Factor Completely $49 x^{2}+84 x+36$ A) $(7 x-6)^{2}$ B) Prime
C) $(7 x+6)(7 x-6)$