At STP the volume of HCl that will result from the reaction of 0.680 L of H₂ and 0.750 L of Cl₂ is ________.
H₂(g) + Cl₂(g) $\rightarrow$ 2 HCl(g)

Question

At STP the volume of HCl that will result from the reaction of 0.680 L of H₂ and 0.750 L of Cl₂ is ________. H₂(g) + Cl₂(g) $\rightarrow$ 2 HCl(g)

Quizplus · Accepted Answer

The balanced chemical equation shows that 1 mole of H₂ reacts with 1 mole of Cl₂ to produce 2 moles of HCl. Since the reaction is at STP and involves gases, the volumes of the reactants and products are in the same ratio as their mole ratios. Given that 0.680 L of H₂ will completely react with 0.680 L of Cl₂ (since it's the limiting reactant), this will produce 2 * 0.680 L = 1.36 L of HCl.

At STP the Volume of HCl That Will Result from the Reaction