If a mixture containing 0.50 moles of N₂ and 1.8 moles of H₂ is allowed to react according to the equation
N₂ + 3H₂ $\rightarrow$ 2NH₃

Question

If a mixture containing 0.50 moles of N₂ and 1.8 moles of H₂ is allowed to react according to the equation N₂ + 3H₂ $\rightarrow$2NH₃

Quizplus · Accepted Answer

The stoichiometry of the reaction indicates that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃. Given the initial amounts, N₂ is the limiting reactant because it will be completely consumed first, determining the maximum amount of product that can be formed. Calculating the mass of the product based on the limiting reactant confirms that 17.0 grams of NH₃ can be produced, making both statements A and B correct.

If a Mixture Containing 0 →\rightarrow→ 2NH3 A) 17

If a Mixture Containing 0 $\rightarrow$ 2NH₃
A) 17