Determine whether the two given lines are perpendicular
-$3 x-4 y=3$
$8 x+6 y=3$

Question

Quizplus · Accepted Answer

The coefficients of $x$ and $y$ in the first equation are $3$ and $-4$, respectively. The coefficients of $x$ and $y$ in the second equation are $8$ and $6$, respectively. The product of the coefficients of $x$ and $y$ in the first equation is $(-3) \cdot (-4) = 12$, and the product of the coefficients of $x$ and $y$ in the second equation is $(8) \cdot (6) = 48$. Since the product of the coefficients of $x$ and $y$ in the two equations is not $-1$, the two lines are not perpendicular.

Determine Whether the Two Given Lines Are Perpendicular - 3x−4y=33 x-4 y=33x−4y=3

Determine Whether the Two Given Lines Are Perpendicular
- $3 x-4 y=3$