Write the equation in slope-intercept form
-$3 x+7 y=41$

A) $y=\frac{3}{7} x+\frac{41}{7}$

B) $y=-\frac{3}{7} x+\frac{41}{7}$

C) $y=-\frac{7}{3} x+\frac{7}{41}$

D) $y=\frac{7}{3} x+\frac{7}{41}$

Question

Write the equation in slope-intercept form
-$3 x+7 y=41$

A) $y=\frac{3}{7} x+\frac{41}{7}$

B) $y=-\frac{3}{7} x+\frac{41}{7}$

C) $y=-\frac{7}{3} x+\frac{7}{41}$

D) $y=\frac{7}{3} x+\frac{7}{41}$

Quizplus · Accepted Answer

To write the equation $3x + 7y = 41$ in slope-intercept form ($y = mx + b$), solve for $y$. Subtract $3x$ from both sides to get $7y = -3x + 41$, then divide everything by $7$ to isolate $y$, resulting in $y = -\frac{3}{7}x + \frac{41}{7}$.

Write the Equation in Slope-Intercept Form - 3x+7y=413 x+7 y=413x+7y=41 A) y=37x+417y=\frac{3}{7} x+\frac{41}{7}y=73​x+741​

Write the Equation in Slope-Intercept Form
- $3 x+7 y=41$ A) $y=\frac{3}{7} x+\frac{41}{7}$