$\left(3 x^{2}+7 x-8\right)+\left(5 x^{2}-11 x+10\right)$
A) $8 x^{2}+4 x+2$
B) $8 x^{2}-4 x+2$
C) $8 x^{2}-18 x+2$
D) $8 x^{2}-4 x+18$

Name: $\left(3 x^{2}+7 x-8\right)+\left(5 x^{2}-11 x+10\right)$ A) $8 x^{2}+4 x+2$ B) $8 x^{2}-4 x+2$ C) $8 x^{2}-18 x+2$ D) $8 x^{2}-4 x+18$
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Question

Quizplus · Accepted Answer

To solve, combine like terms: $3x^2 + 5x^2 = 8x^2$, $7x - 11x = -4x$, and $-8 + 10 = 2$, resulting in $8x^2 - 4x + 2$.

(3x2+7x−8)+(5x2−11x+10)\left(3 x^{2}+7 x-8\right)+\left(5 x^{2}-11 x+10\right)(3x2+7x−8)+(5x2−11x+10) A) 8x2+4x+28 x^{2}+4 x+28x2+4x+2 B) 8x2−4x+28 x^{2}-4 x+28x2−4x+2

$\left(3 x^{2}+7 x-8\right)+\left(5 x^{2}-11 x+10\right)$ A) $8 x^{2}+4 x+2$ B) $8 x^{2}-4 x+2$