Factor completely. If the polynomial cannot be factored, write "prime."
-$8 c^{3}+125$
A) $(2 c+5)\left(4 c^{2}+25\right)$
B) $(2 c-5)\left(4 c^{2}+10 c+25\right)$
C) $(2 c+5)\left(4 c^{2}-10 c+25\right)$
D) $(8 c+5)\left(c^{2}-10 c+25\right)$

Question

Quizplus · Accepted Answer

This polynomial is a sum of cubes, factored as $(a^3 + b^3) = (a + b)(a^2 - ab + b^2)$, where $a = 2c$ and $b = 5$, resulting in option C: $(2c+5)(4c^2-10c+25)$.

Factor Completely 8c3+1258 c^{3}+1258c3+125 A) (2c+5)(4c2+25)(2 c+5)\left(4 c^{2}+25\right)(2c+5)(4c2+25) B) (2c−5)(4c2+10c+25)(2 c-5)\left(4 c^{2}+10 c+25\right)(2c−5)(4c2+10c+25)

Factor Completely $8 c^{3}+125$ A) $(2 c+5)\left(4 c^{2}+25\right)$ B) $(2 c-5)\left(4 c^{2}+10 c+25\right)$