Factor completely. If the polynomial cannot be factored, write "prime."
-$-x^{2}-5 x+14$
A) $(x+2)(x-7)$
B) $-(x-2)(x+7)$
C) $-(x-2)(x-7)$
D) Prime

Question

Quizplus · Accepted Answer

The correct factoring of the given polynomial $-x^{2}-5x+14$ is $-(x-2)(x+7)$. This is because when you factor out the negative sign, the trinomial $x^{2}+5x-14$ can be factored into $(x-2)(x+7)$, and reintroducing the negative sign gives the correct answer.

Factor Completely −x2−5x+14-x^{2}-5 x+14−x2−5x+14 A) (x+2)(x−7)(x+2)(x-7)(x+2)(x−7) B) −(x−2)(x+7)-(x-2)(x+7)−(x−2)(x+7) C) −(x−2)(x−7)-(x-2)(x-7)−(x−2)(x−7) D) Prime

Factor Completely $-x^{2}-5 x+14$ A) $(x+2)(x-7)$ B) $-(x-2)(x+7)$ C) $-(x-2)(x-7)$ D) Prime