Solve.
-$\log _{5}\left(x^{2}-14 x+59\right)=\log _{5} 14$
A) $\{-5,9\}$
B) $\{5,9\}$.
C) $\{5\}$
D) $\varnothing$

Name: Solve. -$\log _{5}\left(x^{2}-14 x+59\right)=\log _{5} 14$ A) $\{-5,9\}$ B) $\{5,9\}$. C) $\{5\}$ D) $\varnothing$
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Question

Quizplus · Accepted Answer

Since the logarithms are equal, the arguments must be equal: $x^2 - 14x + 59 = 14$. Solving the quadratic equation $x^2 - 14x + 45 = 0$ gives the solutions $x = 5$ and $x = 9$. Both values satisfy the original equation.

Solve - log⁡5(x2−14x+59)=log⁡514\log _{5}\left(x^{2}-14 x+59\right)=\log _{5} 14log5​(x2−14x+59)=log5​14 A) {−5,9}\{-5,9\}{−5,9} B) {5,9}\{5,9\}{5,9} C) {5}\{5\}{5}

Solve
- $\log _{5}\left(x^{2}-14 x+59\right)=\log _{5} 14$ A) $\{-5,9\}$ B) $\{5,9\}$
C) $\{5\}$