Solve.
-$\log _{6}(6 x-9)=2$
A) $\left\{\frac{\log _{6} 2+9}{6}\right\}$
B) $\left\{\frac{45}{11}\right\}$
C) $\{39\}$
D) $\left\{\frac{15}{2}\right\}$

Question

Quizplus · Accepted Answer

To solve the equation $\log _{6}(6 x-9)=2$, we first convert the logarithmic equation to its exponential form: $6^2 = 6x - 9$. Simplifying, we get $36 = 6x - 9$. Adding 9 to both sides gives $45 = 6x$, and dividing by 6 gives $x = \frac{45}{6}$, which simplifies to $x = \frac{15}{2}$.

Solve - log⁡6(6x−9)=2\log _{6}(6 x-9)=2log6​(6x−9)=2 A) {log⁡62+96}\left\{\frac{\log _{6} 2+9}{6}\right\}{6log6​2+9​} B) {4511}\left\{\frac{45}{11}\right\}{1145​} C) {39}\{39\}{39} D) {152}\left\{\frac{15}{2}\right\}{215​}

Solve
- $\log _{6}(6 x-9)=2$ A) $\left\{\frac{\log _{6} 2+9}{6}\right\}$ B) $\left\{\frac{45}{11}\right\}$ C) $\{39\}$ D) $\left\{\frac{15}{2}\right\}$